On nonnegative-order first-kind Bessel functions with large argument

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SUMMARY

This discussion focuses on the properties of nonnegative-order first-kind Bessel functions, specifically their behavior for large arguments. The Bessel function of the first kind, denoted as J_n(x), is defined using a series involving the gamma function. For large values of x, the approximation J_n(x) = √(2/(πx)) cos(x - (nπ/2) - (π/4)) holds true, with the cosine term arising from the asymptotic behavior of the function. The discussion emphasizes the significance of the gamma function in this context, particularly for natural numbers n.

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IridescentRain
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Hello.

I'm not terribly proficient with Bessel functions, but I know that those of the first kind are given by
<br /> \begin{eqnarray}<br /> J_n(x) &amp; = &amp; \left(\frac{x}{2}\right)^n\,\sum_{\ell=0}^\infty\frac{(-1)^\ell}{\ell!\,\Gamma(n+\ell+1)}\,\left(\frac{x}{2}\right)^{2\ell},<br /> \end{eqnarray}<br />where \Gamma is the gamma function.

I found in a book that for large x the following is true:
<br /> \begin{eqnarray}<br /> J_n(x) &amp; = &amp; \sqrt{\frac{2}{\pi x}}\,\cos\left(x-\frac{n\pi}{2}-\frac{\pi}{4}\right)\,\left[1+\mathcal{O}(x^{-1})\right]\\<br /> &amp; \approx &amp; \sqrt{\frac{2}{\pi x}}\,\cos\left[x-(2n+1)\,\frac{\pi}{4}\right].<br /> \end{eqnarray}<br />The second line of that last equation is obvious (they just removed every term except the first one from the first line because 1/x^\ell is negligible for large x and \ell\ge1), but where does the cosine come from? How would I begin to prove this?

I'm working with n\in\mathbb{N}\cup\{0\} only, so perhaps this expression is only true for Bessel functions of natural (or zero) order; I wouldn't know. All I know is that for such values of n the gamma function becomes \Gamma(n+\ell+1)=(n+\ell)!.

Thanks in advance for any help!
 
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\cos(x) = \sum^{\infty}_{k=0} (-1)^{k} \frac{x^{2k}}{(2k)!}

Try using that.
 
Thanks, Millennial. I will.
 

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