One dimensional infinite potential well problem

krishnamraju
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hi,
I am not getting idea to solve below problem
A particle of mass m is in a one-dimensional ,rectangular potential well for which V(x)=0 for 0<x< L and V(x)=infinite elsewhere. The particle is intially prepared in the ground state ψ1 with eigen energy E1. Then , at time t=0, the potential is very rapidly changed so that the original wave function remains the same but V(x)=0 for 0<x<2L and V(x)=infinite elsewhere.Find the probability that the particle is in the first,second,third and fourth excited state of the system when t ≥ 0.
could you help me please.
 
on Phys.org
When the potential is changed suddenly the original wavefunction stays the same. To compute the amplitudes of being in any other state then just compute the overlap integral <psi1|phi> where phi is the wavefunction of the excited state. To get the probability find the modulus squared of the amplitude.
 
Dick said:
When the potential is changed suddenly the original wavefunction stays the same. To compute the amplitudes of being in any other state then just compute the overlap integral <psi1|phi> where phi is the wavefunction of the excited state. To get the probability find the modulus squared of the amplitude.


the |phi> is the excited states in the new potential, right??
 
tnho said:
the |phi> is the excited states in the new potential, right??

Sure.
 
Dick said:
compute the overlap integral <psi1|phi> where phi is the wavefunction of the excited state.
Two quick questions:

1. Is this 'overlap integral' the convolution of the wavefunctions in each potential?

2. Is taking this 'overlap integral' in such a situation generally the way to tackle problems such as this?
 
White Ink said:
Two quick questions:

1. Is this 'overlap integral' the convolution of the wavefunctions in each potential?

2. Is taking this 'overlap integral' in such a situation generally the way to tackle problems such as this?

It's not a 'convolution'. That's something else. It's just the integral conjugate(psi1(x))*psi2(x) over the domain of the wavefunctions. And yes, if everything is properly normalized that's all you have to do.
 

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