Op Amp inverting amplifier , help

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The discussion revolves around confusion regarding the calculation of voltage across a 10k resistor in an inverting op-amp configuration. The user initially calculates the voltage using (Va - Vo) but finds discrepancies with the book's method of (Vo - Va). Clarification is sought on the correct approach to determine the output current (Io) and the reasoning behind the voltage calculations. It is emphasized that the voltage across the resistor is equivalent to the output voltage. Understanding the reference points for potential is crucial for accurate analysis in op-amp circuits.
th3plan
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http://i454.photobucket.com/albums/qq261/integralx2/opamp1.jpg

I don't understand why they did something. I found output voltage to be -1.25v , but to find voltage across the 10k resistor, its (Va-Vo)/10k am i correct? cause when i do this and try to calculate the answer for Io its not right, the book does (Vo-Va)/10k . What am i not understanding ? I did mesh or nodal analysis if i wanted something like this i always took higher potential-lower potential divided by resistor . Or maybe which I am not sure, the output is at higher potential then the invertting potential, since its being ampplified. Can someone explain please.

Thanks
 
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The voltage across the resistor is just the output voltage.
 

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