Operations on a State in Different Bases

Click For Summary
SUMMARY

The discussion focuses on the mathematical representation of quantum state operations in different bases, specifically the momentum basis (\boldsymbol{\psi_r}) and position basis (\boldsymbol{\phi_p}). It clarifies that the position operator in the position basis is represented as "multiply by x," while in the momentum basis, it takes the form of i\hbar\partial_p. The conversation emphasizes that although the mathematical forms of operators differ across bases, the eigenvalues remain consistent, representing the same physical outcomes of observations regardless of the basis used.

PREREQUISITES
  • Understanding of quantum mechanics principles, particularly wavefunctions and operators.
  • Familiarity with position and momentum bases in quantum mechanics.
  • Knowledge of mathematical representations of operators, including eigenstates and eigenvalues.
  • Basic proficiency in LaTeX for formatting mathematical expressions.
NEXT STEPS
  • Study the mathematical representation of quantum operators in various bases.
  • Explore the implications of wavefunction collapse in quantum mechanics.
  • Learn about the relationship between eigenstates and observable quantities in quantum systems.
  • Investigate the use of LaTeX for typesetting mathematical expressions in online forums.
USEFUL FOR

Quantum physicists, students of quantum mechanics, and anyone interested in the mathematical foundations of quantum state operations and their implications in different bases.

danmay
Messages
48
Reaction score
0
Say we have the same state [itex]\boldsymbol{\psi_r}[/itex] in momentum basis, or [itex]\boldsymbol{\phi_p}[/itex] in position basis. I want to make either a position observation or a momentum observation. How do I write the operation and the result mathematically, [itex]\mathbf{r} \boldsymbol{\psi}[/itex], [itex]\mathbf{r} \boldsymbol{\phi}[/itex], [itex]\mathbf{p} \boldsymbol{\psi}[/itex], or [itex]\mathbf{p} \boldsymbol{\phi}[/itex]? In terms of the results, which ones would be physically equivalent, assuming the same wavefunction always collapses to the same eigenstate of whatever the observable is. Please ask questions / offer suggestions if I'm not making any sense, because I have a feeling some of it may not.

By the way, is [tex]the same as [itex]? Is there a thread/post/sticky on how to use these markups?[/itex][/tex]
 
Physics news on Phys.org
tex gives you a new line.
itex makes the latex show up in the same line of text as your writing.

The different operators have different forms in different bases. The position operator says "multiply by x" if you are in the position basis, but becomes [itex]i\hbar\partial_p[/itex] in the momentum basis. Similarly for the momentum operator.
 
Matterwave said:
The different operators have different forms in different bases. The position operator says "multiply by x" if you are in the position basis, but becomes [itex]i\hbar\partial_p[/itex] in the momentum basis. Similarly for the momentum operator.

So, for any particular operator, a change of basis would give different mathematical forms to its eigenstates (I assume physically they don't change)? But the eigenvalues would still be the same, right, since they have to be the possible outcomes of observation?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 56 ·
2
Replies
56
Views
5K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 61 ·
3
Replies
61
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K