Optimal Paths: Comparing the Motion of Two Balls on Different Trajectories

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The discussion centers on the motion of two balls, A and B, on different trajectories, questioning which reaches the end faster. While ball A appears to have a shorter path, ball B benefits from gravitational acceleration, potentially increasing its speed. Participants analyze the effects of normal forces and energy conservation, concluding that ball B can achieve a higher horizontal velocity during its descent, allowing it to win the race despite the longer distance. The conversation also touches on the implications of different dip shapes on time differences and the conditions under which ball B maintains contact with the ground. Ultimately, the consensus suggests that ball B finishes first due to its advantageous velocity dynamics.
  • #51
It can be shown that the lab-frame equations, in some normalized units, are: $$ x = ct - \sin t \\ y = 1 - \cos t, $$ where ## t \in [0, 2 \pi ] ##, ## c > 1 ##, and where the units of time and length depend on ##A, g ## and ##V_0##. Attached is a lab-frame trajectory that I plotted with ## c = 10 ##.
 

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  • #52
voko said:
haruspex (and possibly others) objected, reasoning that an inverted cycloid cannot possibly be a path "freely slidden upon" by a particle whose initial horizontal velocity is not zero, because such a path is vertical initially. That argument is flawed, however, because the inverted cycloid is the minimal time path in the initially comoving frame; in the lab frame where ##V_0 \ne 0##, the minimal time path is the trajectory of the particle following a cycloidal path in the initially comoving frame; that path is not a cycloid per se.

Apologies - I had not understood what you giving as the solution. Yes, very neat - thanks.
 
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