Optimized "Homework Solutions for Hard Limits

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Homework Statement


1. lim as n approaches infinity of ((n+1)^5-(n-1)^5)/n^4
2. lim as n to infinity (n!)^2/(2n)!

Homework Equations


The Attempt at a Solution


1.I split it up, got (((n+1)/n)^4)*(n+1)-(((n-1)/n)^4)*(n-1). I try to simplify that down to (n+1)-(n-1) and got 2 as my answer, since the other portion of the limit evaluates to 1. Wolframalpha, however, gave me 10 as the answer.

2. I never seen a problem involving limits with just factorials, so I just guessed that n factorial squared grows faaster than (2n)! so the answer is infinity but wolframalpha says the answer is 0.
 
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freshman2013 said:
I try to simplify that down to (n+1)-(n-1)
How did you simplify it to that?
Just expand (n+1)5 etc. by the binomial theorem.
2. I never seen a problem involving limits with just factorials, so I just guessed that n factorial squared grows faaster than (2n)! so the answer is infinity but wolframalpha says the answer is 0.
In the expansions of each n! on the top and (2n)! on the bottom, do you see which terms will cancel? What will that leave?
 
1. Expand ## (n + 1)^5 ## and ## (n - 1)^5 ##.

2. You guessed wrong. But you don't need to guess - look at the ratio of the (n + 1)th term to the nth term, this is always a good place to start.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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