Optimizing Disk Submersion Height for Maximum Wetted Area

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SUMMARY

The optimal height for positioning a circular disk of radius r in a vertical plane to maximize its wetted area when partially submerged in liquid is determined to be r/√(1+π²). This conclusion is derived from analyzing the geometry of the submerged section of the disk and calculating the exposed area. The discussion emphasizes the importance of visualizing the disk's rotation and the relationship between the submerged and exposed areas to arrive at this solution.

PREREQUISITES
  • Understanding of circular geometry and area calculations
  • Familiarity with calculus, specifically differentiation
  • Knowledge of fluid dynamics principles
  • Ability to visualize geometric shapes in a fluid context
NEXT STEPS
  • Study the principles of fluid dynamics related to submerged objects
  • Learn about the differentiation techniques for optimizing area calculations
  • Explore geometric properties of circles and their applications in engineering
  • Investigate the effects of rotation on fluid dynamics in evaporators
USEFUL FOR

Engineers, physicists, and students studying fluid dynamics or mechanical engineering, particularly those focused on optimizing processes in evaporators and similar systems.

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Homework Statement


A circular disk of radius r is used in an evaporator and is rotated in a vertical plane. If it is to be partially submerged in the liquids as to maximize the exposed wetted area of the disk, show that the center of the disk should be positioned at a height r/ \sqrt{1+\pi^2}

The Attempt at a Solution


I do not know how to start this. Would I differentiate and then determine the when it is zero?
 
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start by picturing the disk in the fluid

the way i have, as it rotates, there will be a disk of wet section, with part of that disk submerged, first calculate the area of the disk, then calculate the area on the submerged section, the difference is the exposed evaporator
 

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