Optimizing RLC Circuit with Extra Resistors for Improved Performance

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The discussion focuses on optimizing an RLC circuit by incorporating additional resistors for enhanced performance. The user struggles with applying standard solutions from a table for series RLC circuits, considering the use of Thevenin equivalents instead. They encounter issues with initial current being zero, complicating integration and analysis of damping behavior. The user compares their derived expression for the circuit's response to a standard solution, noting discrepancies in coefficients. The conversation emphasizes the need to complete calculations by incorporating the capacitor's influence on the current.
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Hello, I am working on this problem
ImageUploadedByPhysics Forums1399243402.897536.jpg


I am having some difficulty finding the right answer. A few points I'd like to expand on so that one can understand my thought process. First off, there is a standard table with the solution to series RLC circuits. I don't think I can use that table with what I have in this circuit. So one idea I have us to modify the circuit to look like what I want with a thevenin equivalent.

If the thevenin idea is wrong, I did nodal analysis and this is what my attempt looks like.
ImageUploadedByPhysics Forums1399243617.704557.jpg


I get an expression but the initial current is Zero, which proves troubling to integrate. I also can't tell the nature of damping in this circuit either
 
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I tried again with the thevenin, which brings me closer to the answer, but their value is

-13.33e^(-.5t)sin(.375t)

Mine is almost the same, but I have that extra -7.5 term that they don't. I get -20.83e^(-.5t)sin(.375t)

ImageUploadedByPhysics Forums1399245106.145250.jpg


ImageUploadedByPhysics Forums1399245125.039762.jpg
 
At t=0 the capacitor is, presumably, fully charged, so the inductor current and voltage at this time will both be 0.

It's a second order system, so the response will be a decaying sinusoid. Where did you copy the general solution from?

What is alpha described as?
 
Here is the table

Alpha is the damping coefficient

ImageUploadedByPhysics Forums1399689560.199109.jpg
 
Maylis said:
Here is the table

Alpha is the damping coefficient
Possibly not. Coefficients are usually dimensionless. Your alpha has units of sec⁻¹.

Your method looks right, but you haven't finished. To determine ic you now have to multiply that derivative by C.
 

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