Orbital Period of satellite in terms of v and r

AI Thread Summary
To determine the orbital period T of a satellite in a circular orbit, the relationship between distance, speed, and time is utilized. The distance for one revolution is the circumference, given by 2πr, and the speed is defined as v. By rearranging the formula T = d/v, it simplifies to T = (2πr)/v. The discussion emphasizes avoiding unnecessary complexity and extra variables, focusing instead on the direct relationship between the orbital path and speed. This approach effectively answers the original question regarding the orbital period.
Cloud 9
Messages
7
Reaction score
0

Homework Statement


"A satellite orbits the Earth in a circular orbit of radius r. If the orbital speed of the satellite is v, what is the orbital period T of the satellite in terms of v and r? You must explain how you derive the expression for the period."

Homework Equations


Speed = distance/time
a = v2/r

The Attempt at a Solution


Distance for 1 revolution of a circle is equal to the circumference. So distance = 2(pi)r
Time to travel 1 revolution = period T

So velocity = speed = 2(pi)r/T

a = v2/r

a = 2(pi)r/T * 1/T

a = 2(pi)r / T2

At this point I would solve for T, but I am not sure if this is valid, what I'm doing? I don't think we are supposed to have an acceleration in there, so I was wondering if there is another equation I could use that relates v and r. Btw this is not graded, it's just a sample test (that we're not turning in) to help us for the real test (on Tuesday). Thanks for any assistance.
 
Last edited:
Physics news on Phys.org
I don't think you even need to bother with the centripetal acceleration equation.

If we have an orbital radius of r, this gives an orbital path distance of 2∏r

T = d / v ---> T = (2∏r) / v
 
If you know the distance per revolution, and you know the velocity, surely you can compute the time of one revolution.
 
bossman27 said:
I don't think you even need to bother with the centripetal acceleration equation.

If we have an orbital radius of r, this gives an orbital path distance of 2∏r

T = d / v ---> T = (2∏r) / v

Oh thanks, so I could have stopped there and solved for T. I guess I made it too complicated. So that answers the question right?
 
Cloud 9 said:
Oh thanks, so I could have stopped there and solved for T. I guess I made it too complicated. So that answers the question right?

Yup, in general you want to use the least amount of extra variables/equations possible.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top