Organic Halide Reaction: Products of Chloroethane and Sodium Hydroxide

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When chloroethane reacts with sodium hydroxide, two potential products can form: ethanol and sodium chloride via a substitution reaction, or ethene, water, and sodium chloride through an elimination reaction. The primary carbon structure of chloroethane influences the reaction pathway, raising questions about the stability of any carbonium ion intermediates involved. Stabilization of a carbonium ion can occur through delocalization, such as in aromatic systems, which affects the likelihood of elimination reactions. The discussion also highlights the importance of determining whether the mechanism is E2 or E1, as this impacts the reaction outcome. Understanding these mechanisms is crucial for predicting the products of the reaction accurately.
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Homework Statement


When reacting chloroethane with sodium hydroxide, what are the products?



The Attempt at a Solution


I think there are two possible solutions to this problem. One possible solution is ethanol and sodium chloride, through a substitution reaction. Another solution could be ethene, water, and sodium chloride, through an elimination reaction. How do I know which solution the question is looking for?
 
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Remember that the carbon is primary in this case. Do you know of any elimination reactions on a primary carbon that aren't stabilized by an adjacent group?
 
What do you mean by stabilized?
 
If the reaction mechanism calls for a carbonium ion intermediate, something that would donate electron density to that carbonium ion would "stabilize" it. If the carbonium ion intermediate could be delocalized somehow as in an aromatic ring or and some other unsaturated system, that would "stabilize" the carbonium ion.
 
The reaction mechanism for the elimination reaction (is it E2 or E1?) involves plucking off an adjacent hydrogen resulting in... what? Is this (primary, secondary or tertiary?) carbonium ion reasonable?
 
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