Orienational order parameter in isotropic systems

AI Thread Summary
In the discussion, the order parameter S in NMR and liquid crystal studies is defined, highlighting its dependence on the angle θ between molecules and a reference direction. It is noted that S equals 0 in isotropic environments, indicating random molecular orientations, while S equals 1 when molecules are perfectly aligned. A participant clarifies that for isotropic distributions, the average value of cos²θ is 1/3, which contributes to S being zero. The calculation involves integrating over the solid angle of 4π, reinforcing the concept of random orientation. Understanding this relationship is crucial for interpreting molecular alignment in various physical contexts.
Liam79
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Hi everyone,

I have what may be a dummy question. In NMR or in the study of liquid crystals for example, an order parameter S is often used:
S=\left\langle\frac{1}{2}\left(3\cos^{2}\theta-1\right)\right\rangle
with \theta the angle of the molecule with a "director" (the magnetic field in NMR, the normal to a membrane for lipids, the global direction in a nematic phase etc). S corresponds to a second-order Legendre polynomial.
I have often read that in an isotropic environment, S=0 whereas when all the molecules are well aligned with the reference vector (director), S=1. I understand why S=1 as \theta=0° but I can't find why S=0 when all the orientations are random.
Can anyone help me?

Liam
 
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For isotropic distribution the average of cos^2 is 1/3.
The average (these brackets) imply an integral over solid angle of 4π.
 
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