Orthogonal Basis for Subspace: Find Solution

  • Thread starter Thread starter hpayandah
  • Start date Start date
  • Tags Tags
    Basis Orthogonal
hpayandah
Messages
18
Reaction score
0
Hi Everyone,
I want to ask if I did this problem correctly.

Homework Statement


Find a orthogonal basis for subspace {[x y z]T|2x-y+z=0}


Homework Equations


X1= [3 2 -4]T, X2=[4 3 -5]T


The Attempt at a Solution


Gram-Schmidt:
F1=X1= [3 2 -4]
F2= X2- ((X2.F1)/||F1||2)F1= [4 3 -5]T + (26/29)[3 2 -4]T


Thanks in advance.
 
Physics news on Phys.org
Hi hpayandah! :smile:

I don't quite get how you obtained the 26 in the end. Could you explain? (Maybe I just miscalculated it).
 
Hi, Thanks for replying, it's the result of:

(X2 . F1) / (||F1||2)

Attached is my work.
 

Attachments

  • 20110709_015.jpg
    20110709_015.jpg
    30.3 KB · Views: 449
Yes, that is correct. You wrote X2 wrong in the OP :smile:
 
micromass said:
Yes, that is correct. You wrote X2 wrong in the OP :smile:
Appreciated.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

Similar threads

Back
Top