Orthogonal Subgroups : on Modules?

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Hi, All:

I have seen Orthogonal groups defined in relation to a pair (V,q) , where V is
a vector space , and q is a symmetric, bilinear quadratic form. The orthogonal
group associated with (V,q) is then the subgroup of GL(V) (invertible linear
maps L:V-->V ), i.e., invertible matrices ( V assumed finite-dimensional), that
preserve the form q, i.e., L in GL(V): q(v1,v2)=q(L(v1),L(v2)).

** Still** I am reading somewhere about what it seems to be an orthogonal
group, but this time associated with a pair (M,q) , where M is not a vector space,
but instead M is a Z-module. I had never seen orthogonal groups extended to
apply to anything other than vector spaces . Does anyone know if this is correct?
If so, what are the properties of these orthogonal groups?

Thanks.
 
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The orthogonal groups are usually defined over the reals with ##q=1##.
Physicists use the Minkowski metric ##q=\operatorname{diag}(-1,1,1,1)## or equivalently ##(1,-1,-1,-1)## and speak also of the orthogonal group, although ##q## is not non degenerate here.

If we pass to integers as scalar area, the lattice group ##SL(2,\mathbb{Z})## is often considered. But of course, we can as well define the orthogonal group for ##\mathbb{Z}-##modules. Since the determinant is ##1## we don't have any difficulties. The properties are less groupwise than on the module level, as we have a discrete area which the groups act on.
 
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The following are taken from the two sources, 1) from this online page and the book An Introduction to Module Theory by: Ibrahim Assem, Flavio U. Coelho. In the Abelian Categories chapter in the module theory text on page 157, right after presenting IV.2.21 Definition, the authors states "Image and coimage may or may not exist, but if they do, then they are unique up to isomorphism (because so are kernels and cokernels). Also in the reference url page above, the authors present two...
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