Oscillation Frequency of superposition of two oscillations of different frequencies

AI Thread Summary
The discussion focuses on finding the frequency of combined motion for two oscillations with different frequencies. In part (a), the angular frequencies are identified as 12π and 13π, leading to periods of 1/6 sec and 2/13 sec, respectively. The combined period is calculated as 2 seconds, resulting in a frequency of 0.5 Hz, which contradicts the provided answer of 6.25 Hz. In part (b), the oscillations are determined to be non-commensurable, indicating that they do not produce periodic motion. The conversation emphasizes the importance of understanding angular frequencies and their relationship to periodicity in oscillatory systems.
Sidnv
Messages
19
Reaction score
0

Homework Statement



Find the frequency of combined motion of the following

(a) x = sin (12pi.t) + cos(13pi.t + pi/4)
(b) x = sin(3t) - cos(pi.t)

Homework Equations



The book I'm using states that if the periods are commensurable ie if there exist 2 integers n1 and n2 such that n1T1 = n2T2 then the period is given by T= n1T1 = n2T2 where n1 and n2 are the smallest possible integers satisfying these conditions.


The Attempt at a Solution



I tried using the formula but the answer I got for a was off and part b should not have a period at all since it is not commensurable. Could anyone help me out please? It would also be really helpful if you could explain how to look at such problems using complex exponentials or else provide me with a link to some material I can read.

Thanks
 
Physics news on Phys.org


Show your work, please. What are the periods of the sine and cosine functions in question A?

ehild
 


The period is given by the sine and cosine functions.

The angular frequency of the sine oscillations in part a is 12 pi and that of the cosine oscillations is 13 pi.

Thus T1 is 1/6 sec and T2 is 2/13 sec.

Thus the period of combined oscillations T = 12*1/6=13*2/13=2sec

Thus frequency should be 0.5 hz. But the answer given is 6.25 hz.

Similarly in part b the ratio of the Time periods is irrational. Hence they are not commensurable and do not give rise to periodic motion.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top