Oxidation number of carbon in (NH4)2C2O4

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    Carbon Oxidation
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Discussion Overview

The discussion centers around determining the oxidation numbers of carbon and nitrogen in the compound (NH4)2C2O4. Participants explore the oxidation states within the context of chemical bonding and charge balance, rather than as part of a homework assignment.

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant proposes that the oxidation number of carbon is +4 and nitrogen is -4.
  • Another participant asserts that the first claim is incorrect but does not provide a definitive answer.
  • A subsequent post requests clarification on why the initial claim is wrong.
  • A different participant explains the reasoning for the oxidation numbers, stating that in the ammonium ion (NH4+), nitrogen has an oxidation number of -3, and in the oxalate ion (C2O42-), carbon has an oxidation number of +3 based on the charge balance with oxygen.
  • A participant points out a typographical error regarding the charge of the ammonium ion, suggesting it should be NH4+ instead of NH4-.
  • Another participant expresses gratitude for the discussion, reiterating their belief that carbon has an oxidation number of +4 in the compound.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the oxidation numbers, with multiple competing views presented regarding the oxidation states of carbon and nitrogen.

Contextual Notes

There are unresolved aspects regarding the assumptions made in calculating oxidation numbers and the implications of charge balance in the ions involved.

Emmanuel_Euler
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What is the Oxidation Number of Carbon and Nitrogen In this compound (NH4)2C2O4?? i think the oxidation number of carbon is (+4) and Nitrogen is (-4).
am i true?? or not?
Note:this is not a homework.
 
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I can't judge whether you are true :-)
I only can tell you that you are wrong.
 
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DrDu said:
I can't judge whether you are true :-)
I only can tell you that you are wrong.
Can you tell me why and where ??
 
So let's take NH4-: H has oxidation number +1 and the oxidation numbers have to sum up to the total charge of the ion, -1. That gives -3 for nitrogen. Same argument with C2O42-: Oxygen has oxidation number -2. Leaves me with +3 for carbon.
 
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@DrDu - confusing typo in your post, it is NH4+ - unless it was premeditated :wink:
 
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Thank you guys. I thought that carbon has a oxidation number of +4 in this compound.
Thank you so much for help.
 

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