Oxidation reaction-which is oxidized?

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SUMMARY

The oxidation reaction discussed involves the equation 2Ag2S(s) + O2(g) = Ag2O(s) + S(s). In this reaction, sulfur (S) is oxidized as it transitions from a -2 to a 0 charge, indicating it loses electrons. Conversely, oxygen (O2) is reduced, changing from a 0 to a -2 charge. Silver (Ag) remains unchanged with a +1 charge throughout the reaction, confirming that it is not oxidized in this context. This analysis highlights the principles of redox reactions, where oxidation and reduction occur simultaneously.

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Homework Statement



2Ag2S(s) + O2(g) = Ag2O(s) + S(s)

Which is being oxidized?

Homework Equations


N/a

The Attempt at a Solution



Reactants:
Ag2S is neutral, with Ag having +1 charge and S having 2- charge.
O2 is neutral

Products:
Ag2O is neutral, with Ag having a 1+ charge and O having -2 charge.
S is neutral.So: Reactants and products have the same net charge?

But, S when from 2- to 0 charge. Therefore, it was oxidized (gained two electrons).
Oxygen went form 0 to 2-. So, it was reduced.
Ag stayed the same. 1+ to 1+.

But, I read that Ag is actually being oxidized.
I'm not really sure what's happening.
 
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I agree with your analysis.
Oxidation and reduction are two sides of the same coin, which is why these reactions are often called redox reactions.

When Ag + 2S -> Ag2S the silver is oxidised from Ag to Ag+ and the sulphur reduced from S to S2-
The silver was already oxidised and did not change. The S2- was oxidised back to S
 
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alphaj said:
But, S when from 2- to 0 charge. Therefore, it was oxidized (gained two electrons).
Oxygen went form 0 to 2-. So, it was reduced.
Ag stayed the same. 1+ to 1+.

Bullseye.
 
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So much more concise than me!
 
Thank you for your help; both of you! I'm relieved that I am thinking about this the right way!
 

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