Oxidation reaction-which is oxidized?

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Discussion Overview

The discussion revolves around identifying which species is oxidized in the oxidation reaction involving silver sulfide (Ag2S) and oxygen (O2) to form silver oxide (Ag2O) and sulfur (S). The scope includes conceptual understanding of oxidation and reduction in the context of a chemical reaction.

Discussion Character

  • Homework-related
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant analyzes the charges of the reactants and products, concluding that sulfur (S) is oxidized as it changes from a 2- to a 0 charge, while oxygen (O2) is reduced from 0 to 2-.
  • Another participant agrees with the analysis and discusses the relationship between oxidation and reduction, noting that silver (Ag) remains unchanged in charge and thus is not oxidized in this reaction.
  • A different participant reinforces the initial claim about sulfur's oxidation and oxygen's reduction, affirming the correctness of the charge analysis.
  • One participant expresses appreciation for the clarity of another's explanation, indicating a preference for concise responses.
  • A final participant expresses gratitude for the assistance received, indicating relief in their understanding of the topic.

Areas of Agreement / Disagreement

There is no clear consensus on whether silver (Ag) is oxidized or not, as some participants assert that it remains unchanged while others suggest it is involved in the oxidation process. The discussion reflects multiple competing views regarding the oxidation states of the elements involved.

Contextual Notes

The discussion includes varying interpretations of oxidation states and the definitions of oxidation and reduction, which may depend on the context of the reaction and the definitions used by participants.

alphaj
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Homework Statement



2Ag2S(s) + O2(g) = Ag2O(s) + S(s)

Which is being oxidized?

Homework Equations


N/a

The Attempt at a Solution



Reactants:
Ag2S is neutral, with Ag having +1 charge and S having 2- charge.
O2 is neutral

Products:
Ag2O is neutral, with Ag having a 1+ charge and O having -2 charge.
S is neutral.So: Reactants and products have the same net charge?

But, S when from 2- to 0 charge. Therefore, it was oxidized (gained two electrons).
Oxygen went form 0 to 2-. So, it was reduced.
Ag stayed the same. 1+ to 1+.

But, I read that Ag is actually being oxidized.
I'm not really sure what's happening.
 
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I agree with your analysis.
Oxidation and reduction are two sides of the same coin, which is why these reactions are often called redox reactions.

When Ag + 2S -> Ag2S the silver is oxidised from Ag to Ag+ and the sulphur reduced from S to S2-
The silver was already oxidised and did not change. The S2- was oxidised back to S
 
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alphaj said:
But, S when from 2- to 0 charge. Therefore, it was oxidized (gained two electrons).
Oxygen went form 0 to 2-. So, it was reduced.
Ag stayed the same. 1+ to 1+.

Bullseye.
 
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So much more concise than me!
 
Thank you for your help; both of you! I'm relieved that I am thinking about this the right way!
 

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