Oxidation reaction-which is oxidized?

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In the oxidation reaction 2Ag2S(s) + O2(g) = Ag2O(s) + S(s), sulfur (S) is oxidized as it changes from a -2 to a 0 charge, indicating it loses electrons. Oxygen (O2) is reduced, transitioning from a 0 to a -2 charge. Silver (Ag) remains unchanged with a +1 charge throughout the reaction. The discussion highlights the relationship between oxidation and reduction, emphasizing that they occur simultaneously in redox reactions. Overall, the analysis confirms the correct identification of oxidized and reduced species in the reaction.
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Homework Statement



2Ag2S(s) + O2(g) = Ag2O(s) + S(s)

Which is being oxidized?

Homework Equations


N/a

The Attempt at a Solution



Reactants:
Ag2S is neutral, with Ag having +1 charge and S having 2- charge.
O2 is neutral

Products:
Ag2O is neutral, with Ag having a 1+ charge and O having -2 charge.
S is neutral.So: Reactants and products have the same net charge?

But, S when from 2- to 0 charge. Therefore, it was oxidized (gained two electrons).
Oxygen went form 0 to 2-. So, it was reduced.
Ag stayed the same. 1+ to 1+.

But, I read that Ag is actually being oxidized.
I'm not really sure what's happening.
 
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I agree with your analysis.
Oxidation and reduction are two sides of the same coin, which is why these reactions are often called redox reactions.

When Ag + 2S -> Ag2S the silver is oxidised from Ag to Ag+ and the sulphur reduced from S to S2-
The silver was already oxidised and did not change. The S2- was oxidised back to S
 
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alphaj said:
But, S when from 2- to 0 charge. Therefore, it was oxidized (gained two electrons).
Oxygen went form 0 to 2-. So, it was reduced.
Ag stayed the same. 1+ to 1+.

Bullseye.
 
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So much more concise than me!
 
Thank you for your help; both of you! I'm relieved that I am thinking about this the right way!
 
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