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I need have this problem check because I have a problem at the last question:

**the probability is 0.6 that a well driller will find a well of water at a depth less than 100 feet in a certain area. Wells are to be drilled for six new homeowners. Assue that finding a well of water at a depth of less than 100 feet is independent from drilling to drilling and that the probability is 0.6 on every drilling. If X is the number of wells of water found. Find:**

*1-P(X>4)*

**My solution: P(X>4)=1-B(4;6,0.6)**

*2-P(X=4)*

**P(X=4)=b(4;6,0.6)**

*3-mean*

**mean=n*p=3.6**

*4-variance*

**Var^2=n*p*(1-p)=1.44**

*5-P(X=mean)*

**Here since mean =3.6, I have problem to find P(X=mean)**

Thank you

B.