Hi, I need have this problem check because I have a problem at the last question: the probability is 0.6 that a well driller will find a well of water at a depth less than 100 feet in a certain area. Wells are to be drilled for six new homeowners. Assue that finding a well of water at a depth of less than 100 feet is independent from drilling to drilling and that the probability is 0.6 on every drilling. If X is the number of wells of water found. Find: 1-P(X>4) My solution: P(X>4)=1-B(4;6,0.6) 2-P(X=4) P(X=4)=b(4;6,0.6) 3-mean mean=n*p=3.6 4-variance Var^2=n*p*(1-p)=1.44 5-P(X=mean) Here since mean =3.6, I have problem to find P(X=mean) Thank you B.