Here's a question my mate asked me to help out with, but I'm a bit stuck, any help would be good. Apologies for not being able to show the circuit (don't know how) so I'll explain it. A parallel circuit has a supply of 1 Vrms and has 2 branches. The first branch has a single capacitor of 2.2 microFarads. The second branch has a resistor of 5 Ohms, and inductor of 0.2 milliHenrys and a capacitor of 30 nanoFarads. The first part was to work out the sesonant frequency of the branch with the 3 components, we both got 2054.7 Hz. The second part was to find the magnitude the magnitude and the phase angle of the current drawn for the entire of the circuit at the frequency of part a (i.e 2054.7Hz). So we worked out that the impedance of the lone capacitor was 35.2 Ohms. From this point we are at a bit confused. Are we right up to this point and where do we go from here? Cheers.