Parallel Line Formula: Solving for y=kx+n with Point (-4,-5)

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The discussion centers on finding the equation of a line parallel to the y-axis that passes through the point (-4, -5). It is clarified that a vertical line cannot be expressed in the slope-intercept form y = kx + n, as this form implies different y-values for different x-values. Instead, the correct representation for a vertical line is x = -4, indicating that the x-coordinate remains constant while y can take any value. The conversation also distinguishes between vertical and horizontal lines, noting that a horizontal line through (-4, -5) would be represented as y = -5. Ultimately, the key takeaway is that vertical lines cannot be expressed in the slope-intercept format.
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Homework Statement



Can somebody use the formula y=kx+n, to present me formula for the line which is parallel to the y-axis and go among the point (-4,-5)?

Homework Equations



y=kx+n

The Attempt at a Solution



k=tg(alpha)

k=tg90

k=\frac{1}{0}

y=\frac{x}{0}

x=0

-4=0

Hm...
 
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If the line is parallel to the Y AXIS then the slope has to be undefined, see why?
 
Last edited:
Physicsissuef said:

Homework Statement



Can somebody use the formula y=kx+n, to present me formula for the line which is parallel to the y-axis and go among the point (-4,-5)?

Homework Equations



y=kx+n

The Attempt at a Solution



k=tg(alpha)

k=tg90

k=\frac{1}{0}

y=\frac{x}{0}

x=0

-4=0

Hm...

you can't multiply by zero like that.

Feldoh said:
If the line is parallel to the Y AXIS then the slope has to be 0, see why?

The y-axis is the vertical one,right?
 
wouldn't that be just x=-4?
 
That's what I believe it will be.
 
I know that it will be x=-4. But please prove it with y=kx+n
rock.freak667, y is the vertical one.
 
The problem is that the two assumptions

k, and n exist such that {(x,y): y=kx+n} is the set of points of the line

{(x,y): x = -4} is the set of points of the line

can not both be true.
 
what is k, what is n?
 
Physicsissuef said:
I know that it will be x=-4. But please prove it with y=kx+n
rock.freak667, y is the vertical one.
You can't. A vertical line, parallel to the y-axis, cannot be written in that form.
 
  • #10
HallsofIvy said:
You can't. A vertical line, parallel to the y-axis, cannot be written in that form.

Why?
 
  • #11
For exactly the reason everyone has been telling you! Writing "y= kx+ n" means that different values of x give different values of y. That is true for all lines except vertical lines. A line parallel to the y-axis has the same value of y for every x. When you learned "y= kx+n", the "slope-intercept" form, you should have learned that every non-vertical line can be written in that form but vertical lines cannot.
 
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  • #12
Ahhh... I undertand now. Thank you very much.
btw- what is that same value for y?
 
  • #13
My mistake. I meant to say the "same x value for every y". In this case, since you tell us one point is (-4, -5) that x value is x= -4 for all y. That's why we can write the equation of that line "x= -4" without mentioning y.

(A horizontal line would have the "same y value for every x". The horizontal line (parallel to the x-axis) passing through (-4, -5) would have y= -5 for every y. Of course, that is of the form "y= kx+ n" with k= 0, n= -5.)
 
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