Parametric equations and lines

Brigada
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Homework Statement


Determine if any of the lines are parallel or identical
L1 (x-8)/4 = (y+5)/-2 = (z+9)/3
L2 (x+7)/2 = (y-4)/1 = (z+6)/5
L3 (x+4)/-8 = (y-1)/4 = (z+18)/-6
L4 (x-2)/-2 = (y+3)/1 = (z-4)/1.5

Homework Equations


L1 pt(8,-5,-9) V<4,-2,3>
L2 pt(-7,4,-6) V<2,1,5>
L3 pt(-4,1,-18) V<-8,4,-6>
L4 pt(2,-3,4) V<-2,1,1.5>

The Attempt at a Solution


I know that if the vectors are scalar multiples, they are either parallel or identical. What I don't know, is after I find out that V(L3) = -2*V(L1). How do I determine if they are parallel or identical. I assume that since one vectors k value is 1.5, it is some multiple of another line, if not they wouldn't have given a 1.X. So L1 L3 L4 are parallel but how could I find if they were identical or not?
 
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After careful consideration, and pulling my head out of the book to think logically, I realized after I find the parallel lines, if a point I chose that satisfies one equation, also satisfies another line equation, they are identical, if its not on the line, it's still parallel, just not identical. That was 1.5 hours wasted on a brain fart!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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