Parametrize a surface and calculating a surface integral

physmatics
Messages
16
Reaction score
0

Homework Statement


Calculate the surface integral I = \int\int f dS of the function f(x,y,z) = \sqrt{1/2 + y^{2}} over the surface S given by x^{2} + 2*y^{2} = 1, 0 \leq z \leq x^{2} + y^{2}. (Clue: parametrize the surface.)

Homework Equations


-

The Attempt at a Solution


The surface is, as far as I can tell, the elliptic cylinder x^{2} + 2*y^{2} = 1, from z = 0 to z = 1.
Now, I have trouble parametrizing the surface. Can I just parametrize it as an ellips in R^{2}? The equation of that ellips would be x = \sqrt{1 - 2*y^{2}}. Then, how do I parametrize the ellips given the equation? And also, why is 'parametrizing the surface' a clue? I really don't get it...
Sorry for clumsy use of LaTeX, I'm not very familiar with it.

Thank you very much!
 
Physics news on Phys.org
You try to parameterize a surface in a way to express it in a nice form that hopefully makes the integral easy. This problem suggests cylindrical-like coordinates. Here's what I would try. Write your cylinder like this:

x^2 + \frac{y^2}{\left(\frac 1 {\sqrt{2}}\right)^2} = 1

This suggests

x = \cos(\theta),\ y = \frac 1{\sqrt{2}}\sin(\theta)

for the ellipse so you could try this parameterization for your surface:

\vec R(\theta,z) =\langle \cos(\theta),\frac 1{\sqrt{2}}\sin(\theta),z\rangle

Try that. It might get a little messy but I think you will find it works. Be brave.:smile:
 
Strictly speaking, what LKurtz gives is the parametrization of the intersection of that cylinder with a plane of constant z. For the surface itself you will need to add z= z.

You then have the surface parameterized by x= cos(\theta), y= (1/\sqrt{2})sin(\theta), z= z so the two-dimensional surface is in terms of the two parameters \theta and z.

We can then write
\vec{R}(\theta, z)= \langle cos(\theta), (1/sqrt{2})sin(\theta), z\rangle

The derivatives with respect to the two parameters,
\vec{R}(\theta, z)_\theta= \langle -sin(\theta), (1/\sqrt{2})cos(\theta), 0\rangle
\vec{R}(\theta, z)_z= \langle 0, 0 , 1 \rangle
are vectors in the tangent plane at each point and their cross product (the "fundamental vector product" the surface), a vector perpendicular to the tangent plane at each point, with "d\theta dz" is the vector differential of surface area and its magnitude is the differential of surface area.
 
HallsofIvy said:
Strictly speaking, what LKurtz gives is the parametrization of the intersection of that cylinder with a plane of constant z.

Huh? Maybe your scroll-down bar isn't working??
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top