Partial Derivatives Maximum and Minimum Values

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SUMMARY

The discussion focuses on finding the absolute maximum and minimum values of the function f(x,y) = 1 + 4x - 5y on the closed triangular region D defined by the vertices (0,0), (2,0), and (0,3). The critical points were determined by calculating the partial derivatives, resulting in fx(x,y) = 4 and fy(x,y) = -5, which do not yield any solutions, indicating no critical points exist within D. Consequently, the next step involves evaluating the function's values on the boundary of the triangular region to identify the extreme values.

PREREQUISITES
  • Understanding of partial derivatives and their significance in multivariable calculus.
  • Familiarity with evaluating functions over closed and bounded sets.
  • Knowledge of the concepts of absolute maximum and minimum values in calculus.
  • Ability to analyze geometric shapes, specifically triangular regions in the Cartesian plane.
NEXT STEPS
  • Evaluate the function f(x,y) on the boundary of the triangular region D.
  • Learn about the method of Lagrange multipliers for constrained optimization.
  • Study the implications of critical points in multivariable functions.
  • Explore graphical methods for visualizing functions of two variables and their extrema.
USEFUL FOR

Students and educators in calculus, particularly those focusing on optimization problems in multivariable functions, as well as anyone seeking to deepen their understanding of partial derivatives and their applications in determining extreme values.

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Homework Statement


Find the absolute maximum and minimum values of f on
the set D.

f(x,y) = 1+4x-5y
D is the closed triangular region with vertices (0,0) (2,0) (0,3)

Homework Equations


To find the absolute maximum and minimum values of a continuous function
on a closed, bounded set :
1. Find the values of f at the critical points of f in D.
2. Find the extreme values of f on the boundary of D.
3. The largest of the values from steps 1 and 2 is the absolute maximum value;
the smallest of these values is the absolute minimum value.

The Attempt at a Solution



So I know to find the values of f at the critical points I must take partial fx and partial fy. Which both should be 0.

But fx(x,y) = 4 and fy(x,y) = -5. How do I set those equal to 0?
 
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As you have deduced those equations do not have solutions. That means that there are no critical points of f, so you must continue to step 2.
 

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