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## Homework Statement

∫1/[(x+a)(x+b)]dx

answer is 1/(a-b) ln[(x+b)/(x+a)] + C

## Homework Equations

## The Attempt at a Solution

1=A/(x+a) + B/(x+b)

1=B(x+a) + A(x+b)

1=Bx+ Ba + Ax +Ab

so 0=Bx+ Ax, 1=Ba+Ab

A=-B, 1=B(a-b)

∫-1/(x+a) +∫1/(x+b)

Im not sure if I am headed in the right direction or not.