B Particle Deceleration in Relativistic Jets?

[metastable]

-1m

Unless I'm mistaken, If a collision with another hovering observer occurred at this point, 2.84*10^(-12)eV kinetic will be measured.

 

[Ibix]

-1m

You've missed a factor of a half here. Anyway, the main point is that one electron changes height by more than a hundred million times more than the other. Why would you expect the energy change (which you know depends on $\Delta h$) to be the same?

 

[metastable]

You've missed a factor of a half here.

Thank you, you are correct.

 

[metastable]

Anyway, the main point is that one electron changes height by more than a hundred million times more than the other. Why would you expect the energy change (which you know depends on ΔhΔh\Delta h) to be the same?

It would require outside energy to lift a stationary electron (to a hovering observer) to a height of + 0.99 * 2.998e+8 m, but no additional outside energy is necessary to "lift" an upward 0.99c electron to the same height. So I guess I don't understand why we would even look at the energy it takes to lift stationary electrons a given distance, because in the scenario we were calculating in which you gave an answer of 3.4keV, I believe the amount of additional outside energy required to lift either the upwards 0.99...c electron the distance it travels in one second, or the upwards 1m/s electron the distance it travels in one second, is precisely 0.

 

[PeterDonis]

I know it seems like I was joking about the readability of the chart since the numbers were all blurred

The numbers being blurred is not the issue. Unblurring the numbers doesn't help. There is no explanation of what these charts are intended to show, where you got the numbers, what the quantities mean, etc. Of course it all makes sense to you because you made the charts and you already know all the background information behind them. But we don't know any of that, and without it your charts are gibberish.

 

[Ibix]

So I guess I don't understand why we would even look at the energy it takes to lift stationary electrons a given distance,

I appear to have confused the scenario you were talking about in #43 with the one you were talking about in #13. It would help if you could focus on one scenario.

In either case, the point is that the work done is the force applied times the distance moved. And the distance moved in unit time is not the same for things moving at different velocities.

 

[metastable]

In either case, the point is that the work done is the force applied times the distance moved.

I'm not contradicting, just presenting the definition of force I'm looking at:

 

[PeterDonis]

just presenting the definition of force I'm looking at

Which is headed by the words "Special Relativity". Which doesn't work when gravity is present, i.e., when spacetime is curved. You cannot use SR in the scenario you are trying to analyze. This has been repeatedly pointed out to you, yet you continue to ignore it.

 

[PeterDonis]

The OP question has been addressed. Thread closed.