Particle Dynamics and Time Problem

AI Thread Summary
When a particle falls through the air, its acceleration decreases from g to zero, leading to a terminal velocity, vf. The acceleration can be expressed as a function of velocity, a=(g/v^2f)(v^2f-v^2), and the discussion focuses on determining the time required for the particle's velocity to be less than vf. Participants suggest starting with the ordinary differential equation dv/dt = (g/v^2f)(v^2f-v^2) to analyze the problem. Clarification is sought on how to approach the forces and gravitational balance in this context. The main goal is to understand the conditions under which the velocity remains below the terminal velocity.
s4orce
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When a particle fall through the air, its initial acceleration a=g diminishes until it is zero, and thereafter it falls at a constant or terminal velocity vf. If this variation of the acceleration can be expressed as a=(g/v^2f)(v^2f-v^2), determine the time needed for the velocity v<vf. Initially the particle falls from rest.
 
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did you mean find the time when v=vf or terminal velocity?
 
find the time for the velocity to become v<vf. (V less than Vf)
 
So, how are you going to start the problem?
 
make the forces and gravitation = to each other? can you help me please?
 
s4orce said:
make the forces and gravitation = to each other? can you help me please?

Start up by setting the ordinary differential equation, dv/dt.
 
dv/dt = (g/v^2f)(v^2f-v^2)? like that? how? can you please show me
 
Ok now, when will v be less than the terminal velocity?
 
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