Particle in a Box: Calculate Probability at Centre

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Homework Statement



A particle is moving in a one dimensional box of infinite height of width 10 Angstroms. Calculate the probability of finding the particle within an interval of 1 Angstrom at the centre of the box, when it is in its state of least energy.

Homework Equations



<br /> \psi _{n}=\sqrt{\frac{2}{L}}sin \frac{n\pi x}{L}<br />

The Attempt at a Solution


The wave function of the particle in the ground state (n=1) is \psi _{1}=\sqrt{\frac{2}{L}}sin \frac{\pi x}{L}. Now, what should I do ?
 
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How does one find the probability amplitude in QM?
 
Square of its wavefunction. I got <tex> \frac{2}{L}sin^2 \frac{\pi x}{L}</tex> Now...
 
Okay, now how do you find the probability on the interval [4 Angstroms,6 Angstroms]?
 
Why between 4 and 6 angstroms ?
 
[STRIKE]Why do you think it's between 4 and 6 angstroms?
[/STRIKE]
EDIT: Err rather I believe it should be from 4.5 to 5.5 angstroms...
 
probability of finding the particle between x & x+dx is {|\Psi|}^{2}

probability of finding the particle between x=a and a=b is \int_{a}^{b}{|\Psi|}^{2}dx
 
What are the limits I should use for the integration?
 
Find a and b for "an interval of 1 Angstrom at the centre of the box".
 
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