- #1
kasse
- 384
- 1
By separation of variables, I have found that
[tex]\frac{-\hbar}{2mg(x)}\frac{d^{2}g(x)}{dx^{2}} = \frac{i}{h(t)}\frac{d h(t)}{dt}[/tex]
Both sides there have to equal the same constant. But why is this constant the total energy of the particle?
[tex]\frac{-\hbar}{2mg(x)}\frac{d^{2}g(x)}{dx^{2}} = \frac{i}{h(t)}\frac{d h(t)}{dt}[/tex]
Both sides there have to equal the same constant. But why is this constant the total energy of the particle?