Particle Kinematics: Find Acceleration & Streamlines

[sara_87]

Homework Statement

The velocity in a steady helical flow of a fluid is given by:
v1= -Ux2, v2=Ux1, v3=V
where U and V are constant.
show that divv is 0 and find the acceleration of the particle at x.
Also determine the streamlines.

Homework Equations

The Attempt at a Solution

to find the divergence, if we differentiate v1 wrt x1, we get 0, and differentiating v2 wrt x2, we get 0 and differentiating v3 wrt x3, we get 0 so the devergence is 0.
but i am having problem finding the acceleration. i know the acceleration is differentiating the velocity with respect to time but what do they mean 'find the acceleration of the particle at x.' ??
Thank you.

 

[Mark44]

Can you elaborate a bit on what Ux2 and Ux1 are, and how they relate to U?

 

[sara_87]

Ux1 and -Ux2 are the components of the velocity vector. U is just a constant.

By the way, the answer to the accelartion part is:
f1= -U^2(x1), f2= -U^2(x2), f3=0
where f1, f2, f3 are the components of the acceleration. But i don't understand how they came to this answer.

 

[cristo]

You have a position vector \vec{x}=(x_1,x_2,x_3) and a velocity vector \vec{v}=(-Ux_1,Ux_2,V), where U and V are constant.

What is the derivative of \vec{v} with respect to time? That is, for the first component, what is the time derivative of -Ux_1 where U is a constant?

Then, how is \dot{\vec{x}} related to \vec{v}?

 

[sara_87]

when we differentiate -Ux1 with respect to time, we get zero. but i think that is wrong because x1 might be depending on the value of t.

Is the derivative of vector x the integral of vector v?

 

[cristo]

but i think that is wrong because x1 might be depending on the value of t.

Exactly, so the derivative of something like -Ux_1 is -U\dot{x_1}, since x_1 is a function of time.

Is the derivative of vector x the integral of vector v?

No: the derivative of \vec{x}, the displacement vector is the velocity. that is, \dot{\vec{x}} \equiv \vec{v}.

 

[sara_87]

Oh right i see. so the way i came to the conclusion that div(v)=0 was wrong.
so for the acceleration, i differentiate v with respect to time.
but then where does the U^2 come from (in the answer)?

 

[cristo]

Oh right i see. so the way i came to the conclusion that div(v)=0 was wrong.

Yea, that's wrong: I didn't read that part.

The divergence is defined as \vec{\nabla}\cdot \vec{A} = (\frac{\partial A_1}{\partial x_1}, \frac{\partial A_2}{\partial x_2},\frac{\partial A_3}{\partial x_3}). Plugging \vec{v} into this will give the result.

so for the acceleration, i differentiate v with respect to time.
but then where does the U^2 come from (in the answer)?

You use the fact that \dot{\vec{x}}\equiv\vec{v} to substitute for the x dots in your differentiated expression.

 

[sara_87]

oh right i see, ofcourse i have substitute, that makes a lot of sense.Thank you.

How do i find the streamlines?
The answer says: helices given parametrically by x1= Acos(Ut) + Bsin(Ut),
x2=Asin(Ut) - Bcos(Ut), x3=Vt+C
where A,B,C are constants.
I understand that x3 is the integral of v3 but how then did they derive x1 and x2?