- #1

chocolatelover

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## Homework Statement

A particle moves along the x axis. Its position is given by the equation x=1.5+2.50t-3.9t^2 with x in meters and t in seconds.

a. Determine its position when it changes direction

b. what is its velocity when it returns to the position it had at t=o

## Homework Equations

## The Attempt at a Solution

a. I would need to take the derivative and set it equal to 0, right?

f'(x)=2.50-7.8t=0

t=(-2.5/-7.8)

I then need to plug t back into the original equation, right?

Would the position when it changes direction be 1.80?

b. What is the velocity when it returns to the position it had at t=0?

2.50-7.8(0)=2.5

Thank you very much