Particle travelling in magnetic field unit vectors

AI Thread Summary
A particle with a charge of -2.00 C moving at a velocity of 1.00 i + 7.00 j encounters a magnetic field of 60.00 k T, leading to the calculation of the force using the equation F = Q (v x B). The cross product was computed using a determinant, resulting in a force of F = -840i + 120j. The discrepancy with the provided answer, which had reversed signs, was clarified by considering the negative charge of the particle. The right-hand rule, adjusted for the negative charge, confirms the calculated force direction. The discussion emphasizes the importance of accounting for charge polarity in magnetic force calculations.
bmxicle
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Homework Statement


a particle with charge -2.00 C initially moves at v = 1.00 i^hat + 7.00 j^hat. If it encounters a magnetic field B = 60.00 k^hat T, find the force on the particle


Homework Equations


F = Q (v x B)


The Attempt at a Solution


I set up a matrix to find the cross product.

v x B = det i j k
1 7 0
0 0 60

If you expand along row three you get (-1)^(3+3) * (60) det i j
1 7

= 60(7i-1j)

===> F=(-2.0 C)(60)(7i - 1j) = -840i + 120 j

The answer i was given has the signs reversed, and i can't figure out why. I've tried it drawing diagrams too and i still got the same answer.
 
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bmxicle said:

Homework Statement


a particle with charge -2.00 C initially moves at v = 1.00 i^hat + 7.00 j^hat. If it encounters a magnetic field B = 60.00 k^hat T, find the force on the particle


Homework Equations


F = Q (v x B)


The Attempt at a Solution


I set up a matrix to find the cross product.

v x B = det i j k
1 7 0
0 0 60

If you expand along row three you get (-1)^(3+3) * (60) det i j
1 7

= 60(7i-1j)

===> F=(-2.0 C)(60)(7i - 1j) = -840i + 120 j

The answer i was given has the signs reversed, and i can't figure out why. I've tried it drawing diagrams too and i still got the same answer.

I think you're right. Whatever answer you were given probably did not take into account the negative charge.

Using the right hand rule (and then flipping your hand 180-deg because a negative particle) confirms your answer qualitatively.
 
thanks, i was wondering if that was the case.
 
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