Particle's Velocity at x_max: F_0, m, v_0, c

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The discussion centers on determining the velocity of a particle at its maximum position, x_max, given its initial conditions and the variable force acting on it. The force is defined as F_x = F_0 sin(cx), and the initial velocity is v_0 with no specific equations provided. Participants suggest integrating the force over the distance to find the relationship between the particle's velocity and its position. There is a consensus that the final velocity expression should involve x_max, along with the constants m, v_0, F_0, and c. The integration process and its implications for the final answer are emphasized as critical to solving the problem.
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Homework Statement



A particle of mass m has initial conditions x_0 = 0 m and v_0 > 0 m/s. The particle experiences the variable force F_x = F_0 sin (cx) as it moves to the right along the x-axis, where F_0 and c are constants.

What is the particle's velocity as it reaches x_max? Give your answer in terms of m, v_0, F_0, and c.

Homework Equations



None.

The Attempt at a Solution



Divide force by m and integrate? V_0 - (F_0 * c) / m ?
 
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You got the idea, but shouldn't the final answer depend on x_max as well?
\int_0^{x_0} \frac{F_0}{m} \sin(c x) = \frac{F_0}{m} \left. -cos(c x)/c \right|_{x = 0}^{x_0} = \frac{F_0}{m c} \left( 1 - \cos(c x_\text{max} \right)
plus v_0, or something like that (check the integration, jotted it down)
 
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