PE/KE-Bullet Hits a Hanging Block?

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SUMMARY

The discussion centers on calculating the kinetic energy (KE) of a bullet before it strikes a hanging block and determining the maximum potential energy (PE) of the block after being hit. The bullet has a mass of 0.05 kg, while the block has a mass of 4 kg and is displaced by 0.50 m. The equations used include PE = mgh and KE = 1/2 mv². Conservation of momentum is essential for finding the bullet's speed, as a significant portion of the bullet's KE is converted into deformation and heating of the block upon impact.

PREREQUISITES
  • Understanding of kinetic energy (KE = 1/2 mv²)
  • Familiarity with potential energy (PE = mgh)
  • Knowledge of conservation of momentum principles
  • Basic concepts of gravitational potential energy in a pendulum system
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  • Study conservation of momentum in inelastic collisions
  • Learn about energy transformation during collisions
  • Explore the effects of deformation and heat on kinetic energy
  • Investigate pendulum motion and energy conservation in swinging systems
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Students in physics, educators teaching mechanics, and anyone interested in understanding energy transfer during collisions and the principles of momentum conservation.

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PE/KE--Bullet Hits a Hanging Block?

Homework Statement


A .05 kg bullet hits a 4 kg block hanging 1.5 m from the ceiling, displacing it by a height of .50 m. What is the KE of the bullet before it hits the block, and what is the max PE of the block?
(So basically, a bullet hits a hanging block and makes it swing upwards by .50 m)

Homework Equations


PE = mgh
KE = 1/2 mv^2


The Attempt at a Solution



I wanted to use 1/2 mv^2 to find the KE of the bullet before hitting the box, but where would I get v from? I figured I could set something equal to the max PE of the block which I'm assuming is 4 (9.8) (.50), but how would I find v?
I figured the max PE of the block would just be mgh, so: 4 (9.8) (.50) But somehow that felt too easy, and I thought there should be more too it?
 
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Merlinnair said:

Homework Statement


A .05 kg bullet hits a 4 kg block hanging 1.5 m from the ceiling, displacing it by a height of .50 m. What is the KE of the bullet before it hits the block, and what is the max PE of the block?
(So basically, a bullet hits a hanging block and makes it swing upwards by .50 m)

Homework Equations


PE = mgh
KE = 1/2 mv^2


The Attempt at a Solution



I wanted to use 1/2 mv^2 to find the KE of the bullet before hitting the box, but where would I get v from? I figured I could set something equal to the max PE of the block which I'm assuming is 4 (9.8) (.50), but how would I find v?
I figured the max PE of the block would just be mgh, so: 4 (9.8) (.50) But somehow that felt too easy, and I thought there should be more too it?

Using conservation of momentum is the only way to find the speed of the bullet.
 


A lot of the KE of the bullet will be used for deformation and heating of the block. So only a small amount of the KE of the bullet will be turned into the GPE of the block.

On the other hand, momentum is conserved. So you could use a momentum calculation to find out what the speed of the bullet was.

Edit: of course, momentum isn't conserved in the vertical direction, since we probably want to model the gravitational field as approximately constant. You could shoot the block horizontally and measure how far it swings out to? The momentum of the bullet would be transferred to the block as if the block were a pendulum.
 
Last edited:

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