- #1
leolaw
- 85
- 1
I am always confused with rms value and peak value, so here is the problem:
What will be the peak value of the current of a well-insulated [tex]0.03\mu F[/tex] capacitor connected to a 2.0-kV(rms) 720-Hz line?
So first I find the reactance of the capacitor, which is:
[tex]X_c=\frac{1}{2\pi fC}[/tex]
[tex]7.4k \Omega[/tex]
and then [tex]V_{rms} = I_rms * X_c[/tex]
[tex] 2*10^3 = I_{rms} (7.4 * 10^3)[/tex]
[tex] I_{rms} = 2.7 * 10^{-1} A[/tex]
so is this the right answer, or do i have to multiply it by [tex]\sqrt{2}[/tex] to get the peak value?
What will be the peak value of the current of a well-insulated [tex]0.03\mu F[/tex] capacitor connected to a 2.0-kV(rms) 720-Hz line?
So first I find the reactance of the capacitor, which is:
[tex]X_c=\frac{1}{2\pi fC}[/tex]
[tex]7.4k \Omega[/tex]
and then [tex]V_{rms} = I_rms * X_c[/tex]
[tex] 2*10^3 = I_{rms} (7.4 * 10^3)[/tex]
[tex] I_{rms} = 2.7 * 10^{-1} A[/tex]
so is this the right answer, or do i have to multiply it by [tex]\sqrt{2}[/tex] to get the peak value?