Peak wavelength and Spectral Bandwidth

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Homework Help Overview

The discussion revolves around calculating the peak wavelength and spectral bandwidth of GaAs and silicon LEDs at two temperatures: liquid nitrogen temperature (77 K) and room temperature (300 K). The original poster attempts to determine which material would be a better emitter based on these calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definitions and implications of peak wavelength and spectral bandwidth, questioning their meanings and relevance to the concept of a "better emitter." There is an attempt to connect energy emission to wavelength, with some participants suggesting that lower wavelengths correlate with higher energy.

Discussion Status

The discussion is ongoing, with participants raising questions about the definitions of key terms and their implications for the original poster's inquiry. Some guidance has been offered regarding the interpretation of "better emitter," but no consensus has been reached on the definitions or the relationship between energy and wavelength.

Contextual Notes

Participants are encouraged to think critically about the parameters involved in the problem, particularly in relation to LEDs, and to clarify their understanding of the associated concepts.

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Homework Statement


Calculate the expected peak wavelength and spectral bandwidth (in units of wavelength) of the
emission for both a GaAs and silicon LED at liquid nitrogen temperature (77 K) and room temperature (300 K). Which of these cases would you expect to result in the best emitter and why?

Homework Equations


λg = hc/Eg
λg: maximum wavelength
λg [μm] = 1.24/Eg

Spectral bandwidth = (1.8kbT) / ħ

The Attempt at a Solution


λg: band gap represents minimum energy, or maximum wavelength for which an electron-hole pair can be excited

GaAs Eg: 1.43 eV
Si Eg: 1.14 eV

λg [μm] = 1.24/1.43 = 0.867 μm (maximum wavelength for GaAs)

λg [μm] = 1.24/1.14 = 1.088 μm (maximum wavelength for Si)

---

Spectral bandwidth = (1.8kb*300k) / ħ = 3.928*1013Hz
Expressing this in units of wavelength, I've used the relation between frequency and wavelength:

λ=c/f = c / 3.928*1013Hz
=7.6*10-6m

Spectral bandwidth = (1.8kb*77k) / ħ = 1.008*1013Hz = 2.9*10-5m/s
Expressing this in units of wavelength, I've used the relation between frequency and wavelength:

λ=c/f = c / 1.008*1013Hz
= 2.9*10-5m

So I think I've got the correct peak wavelength and spectral bandwidth, I'm not sure about the last question though or how I can quantify if one is a better emitter than the other. Any help would be much appreciated!
 
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I would interpret "better emitter" as "brighter", meaning more total energy is emitted. You do have relevant information here.

What does the peak wavelength measure? Peak of what?
What does the spectral bandwidth measure? Bandwidth of what?
 
I'm guessing greater energy = better emitter = lower wavelength
 
Question is asked in regards to LEDs
 
Are you saying that longer wavelengths always equal more energy? So the energy given off by a nuclear explosion in gamma rays is less than the energy given off by a glowing coal in the infrared? Are you sure?

Again, what does the peak wavelength measure? Peak of what? What does the spectral bandwidth measure? Bandwidth of what? How are those things defined?

I know it's about LEDs. I'm asking you to think through the meaning of those parameters. "It's the bandwidth" and "it's about LEDs" are not an explanation. What is it that has a width? What are the axes of the associated graph?
 

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