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Pelican Flying Problem

  1. Oct 12, 2014 #1
    A pelican flying along a horizontal path drops
    a fish from a height of 4.9 m. The fish travels
    7.5 m horizontally before it hits the water
    below.
    What was the pelican’s initial speed? The
    acceleration of gravity is 9.81 m/s^2
    Answer in units of m/s


    If the pelican was traveling at the same speed
    but was only 3.0 m above the water, how
    far would the fish travel horizontally before
    hitting the water below?
    Answer in units of m


    Can someone help me i have no idea how to solve this im lost.
     
  2. jcsd
  3. Oct 12, 2014 #2

    BvU

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    Sure. You did well on nuber one of the template. Now help us to provide adequate assistance (at the right level) by also completing 2 and 3. PF rules don't allow us to help if you don't . Why ? See the guidelines !

    1. The problem statement, all variables and given/known data
    2. Relevant equations
    3. The attempt at a solution

    And eh, welcome to PF !
     
  4. Oct 12, 2014 #3
    ok number 2 is

    vx
    dx 7.5
    t

    vfY
    voY 0
    aY -9.8
    dY -4.9
    t

    i used this equation

    s=1/2gt^2

    but i can get the right answers

    and number 3 is

    i used that equation but i can´t get the right answer


    and sorry im new idk how to ask correctly here and stuff
     
  5. Oct 12, 2014 #4

    NascentOxygen

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    When you use this equation, what is the result telling you?
     
  6. Oct 12, 2014 #5

    BvU

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    What is s ?
     
  7. Oct 12, 2014 #6

    s is speed
     
  8. Oct 12, 2014 #7
    like i get the wrong answer all the time
     
  9. Oct 13, 2014 #8

    BvU

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    Like you multiply m/s^2 with s^2 and you are surprised you don't get something with the dimension of m/s ?
     
  10. Oct 13, 2014 #9

    haruspex

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    No, in the standard SUVAT equations s is distance. Speeds, initial and final, are represented by u and v.
     
  11. Oct 13, 2014 #10
    No is just that i get the answer wrong not the dimensions
     
  12. Oct 13, 2014 #11

    NascentOxygen

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    Staff: Mentor

    So now apply the equation I quoted, and describe what it can tell you. (Remember, s is not speed.)
     
  13. Oct 13, 2014 #12
    I used the equation Vx=deltaX/t

    And i got it right thanks tho ;)
     
  14. Oct 14, 2014 #13

    NascentOxygen

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    Staff: Mentor

    That's the only equation you used? Since you showed no working here, we'll have to accept your word that you solved it correctly.
     
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