# Pelican Flying Problem

1. Oct 12, 2014

### Mitxigan

A pelican flying along a horizontal path drops
a fish from a height of 4.9 m. The fish travels
7.5 m horizontally before it hits the water
below.
What was the pelican’s initial speed? The
acceleration of gravity is 9.81 m/s^2
Answer in units of m/s

If the pelican was traveling at the same speed
but was only 3.0 m above the water, how
far would the fish travel horizontally before
hitting the water below?
Answer in units of m

Can someone help me i have no idea how to solve this im lost.

2. Oct 12, 2014

### BvU

Sure. You did well on nuber one of the template. Now help us to provide adequate assistance (at the right level) by also completing 2 and 3. PF rules don't allow us to help if you don't . Why ? See the guidelines !

1. The problem statement, all variables and given/known data
2. Relevant equations
3. The attempt at a solution

And eh, welcome to PF !

3. Oct 12, 2014

### Mitxigan

ok number 2 is

vx
dx 7.5
t

vfY
voY 0
aY -9.8
dY -4.9
t

i used this equation

s=1/2gt^2

but i can get the right answers

and number 3 is

i used that equation but i can´t get the right answer

and sorry im new idk how to ask correctly here and stuff

4. Oct 12, 2014

### Staff: Mentor

When you use this equation, what is the result telling you?

5. Oct 12, 2014

### BvU

What is s ?

6. Oct 12, 2014

### Mitxigan

s is speed

7. Oct 12, 2014

### Mitxigan

like i get the wrong answer all the time

8. Oct 13, 2014

### BvU

Like you multiply m/s^2 with s^2 and you are surprised you don't get something with the dimension of m/s ?

9. Oct 13, 2014

### haruspex

No, in the standard SUVAT equations s is distance. Speeds, initial and final, are represented by u and v.

10. Oct 13, 2014

### Mitxigan

No is just that i get the answer wrong not the dimensions

11. Oct 13, 2014

### Staff: Mentor

So now apply the equation I quoted, and describe what it can tell you. (Remember, s is not speed.)

12. Oct 13, 2014

### Mitxigan

I used the equation Vx=deltaX/t

And i got it right thanks tho ;)

13. Oct 14, 2014

### Staff: Mentor

That's the only equation you used? Since you showed no working here, we'll have to accept your word that you solved it correctly.

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