How Do You Derive the Equation of Motion for an Inverted Pendulum with Springs?

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The discussion focuses on deriving the equation of motion for an inverted pendulum connected to two equal springs. Participants seek clarification on the terms involving sine and cosine in the equation, particularly how they relate to the spring constants and the geometry of the system. The original poster acknowledges confusion regarding the derivation and requests further explanation. There is a mention of a lack of clarity in the question initially posed, which was later edited for better understanding. The conversation emphasizes the need for a clear formulation of the problem to facilitate effective discussion and solutions.
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Can someone explain how they got the term with the red box
I understand the kl/2 but not the sin and cos part

**Question** Consider the inverted pedulum connected to two equal springs both with constant k. Springs are undelfected when the mass is in the verticle position. If the rod is of length l and the spring are connected at l/2 find the equation of motion.

http://img442.imageshack.us/img442/4896/24111q.jpg
 
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2slowtogofast said:
Can someone explain how they got the term with the red box
I understand the kl/2 but not the sin and cos part
http://img442.imageshack.us/img442/4896/24111q.jpg

If that picture represents the total problem as presented, then there is no solution, as no question is asked?
 
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Sorry I was on my phone and forgot the question I edited my orginal post
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...

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