Pendulum string and ball question

AI Thread Summary
A physics problem involving a simple pendulum with a 0.58 m string and a small ball seeks to determine the time it takes for the ball to reach its greatest speed after being released. The frequency of the pendulum is calculated to be 0.654 cycles per second, leading to a period of 1.53 seconds. The time to reach maximum speed is derived as T/4, resulting in approximately 0.766 seconds. This timing aligns with the ball reaching its peak speed at the lowest point of the swing. The discussion clarifies the relationship between frequency, period, and the dynamics of pendulum motion.
osustudent2010
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Hi! Here is a phyics problem I am having trouble with:

A simple pendulum is made from a 0.58 m long string and a small ball attached to its free end. The ball is pulled to one side through a small angle and then released from rest. After the ball is released, how much time elapses before it attains its greatest speed?

so far the only thing I've found is the frequency = .654 cycles/sec
i know its greatest speed would be when the pendulum is completely vertical (theta = 0), I just can seem to relate the two

any help would be appricated! thanks!
 
Physics news on Phys.org
You need this baby: T/4.Do you know why?

Daniel.

P.S.What's the definition of a period of oscillation...?
 


Hi there! Thanks for reaching out with your physics problem. Let's see if we can work through it together.

First, let's define some variables to make things clearer. Let's say that the length of the string is L = 0.58 m, the angle the ball is pulled to is θ, and the time it takes for the ball to reach its greatest speed is t.

We know that the frequency of a simple pendulum is given by f = 1/T, where T is the period of the pendulum. The period is the time it takes for one full cycle, or one swing from one side to the other and back again. In this problem, we are given the frequency, f = 0.654 cycles/sec, so we can find the period by taking the inverse: T = 1/f = 1/0.654 = 1.53 seconds.

Now, to relate the period to the time it takes for the ball to reach its greatest speed, we can use the formula for the period of a simple pendulum: T = 2π√(L/g), where g is the acceleration due to gravity, which is approximately 9.8 m/s^2. We can rearrange this equation to solve for t: t = T/4 = π√(L/g)/2 = 0.766 seconds.

So, it will take approximately 0.766 seconds for the ball to reach its greatest speed after it is released. This makes sense because the ball will reach its greatest speed when it is at the bottom of its swing, which is half of a full cycle.

I hope this helps! Let me know if you have any other questions or if anything is unclear. Good luck with your physics problem!
 
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