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Percent uncertainty?

  1. Sep 14, 2004 #1
    hi, I'm attempting a physics problem... it is:
    What, roughly, is the percent uncertainty in the volume of a spherical beach ball whose radius is r= 2.86 plus or minus 0.09 m.
    Now, I tried to find the percent uncertainty by just doing .09/2.86, but I'm assuming I need to do something with the radius (in the way of changing it to the full volume...) before I can calculate this.
    I know that to find the volume it would be 4/3 pi R cubed, but after that... how does the volume correlate to the .09? Does that need to be altered as well? I know the answer is 9% but I would like to actually understand how the question is done!
    I'm just confused. Any help would be greatly appreciated!
     
  2. jcsd
  3. Sep 14, 2004 #2

    Gokul43201

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    General Rule : When quantities multiply, the relative errors in those quantities add up.

    The volume is proportional to the cube of the radius. As a result the percent error in volume is thrice the percent error in the radius.
     
  4. Sep 14, 2004 #3
    ok... so since I cube the radius, I multiply the % error by 3...
    ah. and that gives me 9%.
    You are a genius. Why must physics profs supply us with pages and pages of calculations when you can solve a problem like THAT instead...
    Thanks :)
     
  5. Sep 15, 2004 #4

    Chronos

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