Period of a Pendulum and moment of inertia

AI Thread Summary
The discussion focuses on calculating the period of a hollow spherical ornament acting as a physical pendulum. The formula provided for the period is T = 2Pi*(sqrt(I/mgL), but the value of L is not given, leading to confusion. Participants suggest that L represents the distance from the pivot point to the center of mass of the sphere. Clarification is sought on how to derive L based on the ornament's attachment method. The conversation emphasizes understanding the relationship between torque, moment of inertia, and the physical setup of the pendulum.
Quincy
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Homework Statement



A holiday ornament in the shape of a hollow sphere with mass 1.0×10−2 kg and radius 5.0×10−2 m is hung from a tree limb by a small loop of wire attached to the surface of the sphere. If the ornament is displaced a small distance and released, it swings back and forth as a physical pendulum. Calculate its period. (You can ignore friction at the pivot. The moment of inertia of the sphere about the pivot at the tree limb is (5/3)MR^2.)

Homework Equations



T = 2Pi*(sqrt(I/mgL))

The Attempt at a Solution



This is the only formula I know for the period, but the problem doesn't give the value of L. Is there another formula for the period?
 
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You're given enough info to figure out what L is. Think about what exactly L is defined as. It's the distance between what two points?
 
Quincy said:

Homework Statement



A holiday ornament in the shape of a hollow sphere with mass 1.0×10−2 kg and radius 5.0×10−2 m is hung from a tree limb by a small loop of wire attached to the surface of the sphere. If the ornament is displaced a small distance and released, it swings back and forth as a physical pendulum. Calculate its period. (You can ignore friction at the pivot. The moment of inertia of the sphere about the pivot at the tree limb is (5/3)MR^2.)

Homework Equations



T = 2Pi*(sqrt(I/mgL))

The Attempt at a Solution



This is the only formula I know for the period, but the problem doesn't give the value of L. Is there another formula for the period?

I think it is saying that it is not hanging. It is attached by a loop. Draw a loop around the limb and then draw the ornament attached to the loop.
 
Hi Quincy! :smile:

(have a square-root: √ and a pi: π and try using the X2 tag just above the Reply box :wink:)
Quincy said:
This is the only formula I know for the period, but the problem doesn't give the value of L. Is there another formula for the period?

Then invent a formula! :wink:

Find the torque (moment) of the weight at a typical angle, and then use the formula τ = Iα to get an (approximately) shm equation. :smile:
 
tiny-tim said:
Hi Quincy! :smile:

(have a square-root: √ and a pi: π and try using the X2 tag just above the Reply box :wink:)


Then invent a formula! :wink:

Find the torque (moment) of the weight at a typical angle, and then use the formula τ = Iα to get an (approximately) shm equation. :smile:


Wouldn't you still need that distance for I?
 
vela said:
You're given enough info to figure out what L is. Think about what exactly L is defined as. It's the distance between what two points?

Oops, I misread the problem, I was thinking it was attached to a wire with some length instead of a loop.
 
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