Person's Distance from Shore After Moving 3m: Momentum & Center of Mass

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A 50 kg person on a 75 kg boat starts 6 m from shore and walks 3 m towards the shore, prompting the boat to move in the opposite direction due to conservation of momentum. The center of mass of the system remains fixed, meaning the boat moves a smaller distance than the person. The final distance of the person from the shore is calculated to be 4.2 m. Momentum conservation is crucial in determining the relationship between the person's and the boat's movements. Understanding the center of mass helps clarify how the system's overall position changes as the person moves.
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A 50 kg person at the left end of a 75kg boat is 6 m from shore. The person walks to the other end of the boat 3m away. How far is the person from the shore now? The system center of mass fixed in space so as the person moves right, the boat moves left.

I know that the person moves 3 m to the right but how do I know how much the boat moves to the left? The answer is that the person will end up 4.2 m from shore, but how do I get there. If the person starts at 6 meter away and walks three meters towards the direction of the shore, the boat must travels a smaller distance relative to the person. This unit we're doing is on momentum and center of mass. I don't see how momentum will affect the result here, but maybe I am wrong. However, how does center of mass come into play here?
 
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take into account that weight has an affect on momentum (p = mv). I have no clue how center of mass comes to play since they don't provide any velocity. hmmm maybe the displacement you calculated is where the center of mass is? wait for other posters to confirm this
 
Simply use the fact that momentum is conserved, which will give you a relation between the person's and the boat's velocity, and displacement.
 
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