Phase Difference of Transfer Function H(jw)

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To determine the phase difference between the output (Vo) and input (Vi) of a transfer function H(jw), the phase angle can be calculated using the formula tan^{-1}(Im(H)/Re(H)). A positive phase angle indicates that the output leads the input, while a negative phase angle indicates that the output lags the input. This distinction is crucial for understanding the relationship between Vo and Vi in system dynamics. The discussion emphasizes the importance of clarity in interpreting phase angles in transfer functions. Understanding these concepts is essential for analyzing control systems effectively.
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Homework Statement


If I have a transfer function H(jw)= |\frac{V_o}{V_i}|. I need to find the phase difference between Vo and Vi.


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The Attempt at a Solution


The phase angle is tan^{-1}(\frac{Im(H)}{Re(H)}). My problem is that if I get a positive angle, does this mean that the Output leads or lags the input? I can't find this explained clearly in any text.
 
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A positive phase difference is a lead. A negative phase difference is a lag.
 
nicktacik said:

The Attempt at a Solution


The phase angle is tan^{-1}(\frac{Im(H)}{Re(H)}). My problem is that if I get a positive angle, does this mean that the Output leads or lags the input? I can't find this explained clearly in any text.

Leads.
 
Thanks.
 
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