Photoelectric Effect difficulties

AI Thread Summary
The discussion centers on calculating the maximum kinetic energy of emitted electrons when light with a frequency double the threshold frequency strikes a metal surface. The threshold frequency is given as 5.6 × 10^14 Hz, leading to a striking frequency of 1.12 × 10^15 Hz. The relevant equations include E=hv for photon energy and W=hFo for work function. The confusion arises in determining how much energy is used to free the electron and what happens to the excess energy. Understanding these concepts is crucial for solving the problem accurately.
ysidfa
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Homework Statement


"The threshold frequency of a particular metal surface is 5.6 × 1014 Hz. Calculate the maximum kinetic energy of emitted electrons if the frequency of the light striking the metal surface is double the threshold frequency."
Taken from AQA Physics Exam 2009

Homework Equations


E=hv, W=hFo


The Attempt at a Solution


I tried working out double the threshold freq. and then going into finding the KEmax from there. Got Really confuzed... :(
 
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ysidfa said:

Homework Statement


"The threshold frequency of a particular metal surface is 5.6 × 1014 Hz. Calculate the maximum kinetic energy of emitted electrons if the frequency of the light striking the metal surface is double the threshold frequency."
Taken from AQA Physics Exam 2009

Homework Equations


E=hv, W=hFo

The Attempt at a Solution


I tried working out double the threshold freq. and then going into finding the KEmax from there. Got Really confuzed... :(
Assume the photon with double the threshold frequency gives all its energy to the electron. How much is used in freeing the electron from the surface? What happens to the rest of the energy?

AM
 

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