Can a photon be said to have a temperature? I want to know if temperature is still related to kinetic energy in this instance. If so, what determines its kinetic energy?
I wonder if you agree with Russ Watters that photons have no kinetic energy? Isn't that what determines their frequency?Originally posted by chroot
So the photons do not individually have a temperature; but in large numbers you can describe the spectrum by a characteristic temperature.
We may be descending into semantics -- but I wouldn't call E = pc "kinetic energy." I'd just call it "energy."Originally posted by (Q)
Doesn’t this represent the kinetic energy of a photon?