Photons effected by gravity of a Blackhole?

sinesawsquare
Messages
2
Reaction score
0
Hello,

New to this forum. Very fascinated with physics. Started as a fascination with waveforms, sound, acoustics, and quickly spiraled into an infinite fascination with physics in general, specially particle physics at a quantum level and general relativity at a cosmic level and nuclear chemistrty in stars.

Anyways, bla bla bla about me here is a question I have been hung up on for many months.

I read very many books and no matter how many times I have it explained and how many examples I see I do not get this:

How does a black hole "pull" in photons? I currently understand that we observe mass to attract mass and we call it gravity. SO how can a black hole use gravity to pull on massless particles such as the photon.

Vice versa: how does a massless particle such as a photon "push" on massive particles such as gas clouds in space.

why do photons seem to act like massive particles.

I have many more questions in this same scope but do not want to waste your time by listing them one by one in this thread. I came here because I am absolutely entranced by physics and want to increase my understanding. I want to visualize these things in my head.

Anyways, if this would be more appropriate in another forum please move it. Links to similar threads would be appreciated if you think it would answer my question. Thank you to anybody who reads my post and thank you to anyone that sheds some light (no pun intended) on the situation.
 
Physics news on Phys.org
sinesawsquare said:
How does a black hole "pull" in photons?
The mass of the black hole curves spacetime, this influences all objects. So also objects that have no mass!

sinesawsquare said:
I currently understand that we observe mass to attract mass and we call it gravity.
Mass certainly attracts other masses but it also attracts massless things.

Mass curves spacetime, so two masses, in general (it's not linear), curve spacetime even more. But the attraction is due to the curvature, and the attraction applies to all objects, also objects that have no mass.
 
You might want to check the Frequently Asked Relativity Questions sub-forum:
https://www.physicsforums.com/forumdisplay.php?f=210

How does a black hole "pull" in photons? I currently understand that we observe mass to attract mass and we call it gravity. SO how can a black hole use gravity to pull on massless particles such as the photon.
https://www.physicsforums.com/showthread.php?t=511173


how does a massless particle such as a photon "push" on massive particles such as gas clouds in space.
https://www.physicsforums.com/showthread.php?t=512541
 
Last edited by a moderator:
This is awesome. Thank you for these answers and these links.
 
Thread 'Can this experiment break Lorentz symmetry?'
1. The Big Idea: According to Einstein’s relativity, all motion is relative. You can’t tell if you’re moving at a constant velocity without looking outside. But what if there is a universal “rest frame” (like the old idea of the “ether”)? This experiment tries to find out by looking for tiny, directional differences in how objects move inside a sealed box. 2. How It Works: The Two-Stage Process Imagine a perfectly isolated spacecraft (our lab) moving through space at some unknown speed V...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. The Relativator was sold by (as printed) Atomic Laboratories, Inc. 3086 Claremont Ave, Berkeley 5, California , which seems to be a division of Cenco Instruments (Central Scientific Company)... Source: https://www.physicsforums.com/insights/relativator-circular-slide-rule-simulated-with-desmos/ by @robphy
In Philippe G. Ciarlet's book 'An introduction to differential geometry', He gives the integrability conditions of the differential equations like this: $$ \partial_{i} F_{lj}=L^p_{ij} F_{lp},\,\,\,F_{ij}(x_0)=F^0_{ij}. $$ The integrability conditions for the existence of a global solution ##F_{lj}## is: $$ R^i_{jkl}\equiv\partial_k L^i_{jl}-\partial_l L^i_{jk}+L^h_{jl} L^i_{hk}-L^h_{jk} L^i_{hl}=0 $$ Then from the equation: $$\nabla_b e_a= \Gamma^c_{ab} e_c$$ Using cartesian basis ## e_I...

Similar threads

Replies
21
Views
2K
Replies
26
Views
3K
Replies
12
Views
2K
Replies
8
Views
2K
Replies
1
Views
2K
Replies
9
Views
2K
Replies
19
Views
3K
Back
Top