Physical Asymptote Homework: Trajectory y=x^4-x^2 & Limit y(x)=h

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The discussion revolves around plotting the trajectory defined by the equation y = x^4 - x^2 within the constraints of a particle's motion in the x-y plane, where y is limited between 0 and h. The limit as x approaches infinity for this trajectory is infinity, but due to the boundary condition, it can be interpreted that y approaches h, suggesting y = h may represent a horizontal asymptote. Clarification is sought on the original problem statement to better understand the requirements for plotting. The trajectory's appearance will vary based on the chosen value of h, which must be assigned to visualize the plot accurately. The conversation emphasizes the importance of defining h to proceed with the plotting process effectively.
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Homework Statement


For example particle performs a motion in x-y plane. In y there are walls from both side so particle can go in y direction from zero to h. I need to plot trajectory. If I got trajectory y=x^4-x^2 then
\lim_{x\to \infty}y(x)=\infty[/B]<h2>Homework Equations</h2><h2>The Attempt at a Solution</h2> <br /> If I got trajectory y=x^4-x^2 then<br /> \lim_{x\to \infty}y(x)=\infty, but because of the condition I may say that <b>\lim_{x\to \infty}y(x)=h. Maybe then y=h is some natural horisontal asymptote?</b>[/B]
 
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Hi. It's hard to understand what your problem exactly is. Could you clarify it maybe by giving its original statement?
If you are asked to plot a two-dimensional trajectory parametrized by:
y = x4–x2,
Under the constraint: ymax= h,
Then it gives you a natural constraint on x as well, as a function of h; if you need to plot this you'll have to assign an arbitrary value to h so that you can plot something.
Now depending on this value, your plot will not always look the same but that's all you can do with the given information...
 
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