Physical Science Question on Electrical Power and Energy

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The electric space heater operates at 1800 watts, drawing 15.0 A from a 120 V source for an average of 5 hours daily. Over 30 days, it consumes 270 kWh, costing $27 at a rate of $0.10 per kWh. For a family of four, the annual electricity usage totals 48,000 kWh, leading to significant coal consumption due to the 40% efficiency of coal power plants. Calculating the coal burned involves converting the energy usage into mass, considering the energy released per kilogram of coal. The discussion emphasizes understanding power, energy, and efficiency in practical applications.
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1. An electric space heater draws 15.0 A from a 120 V source. It is operated, on average, for 5.0h (hours) each day. a) How much power does the heater use and b) At $.10 per kWh, what does it cost to operate the heater for 30 days?
2. Suppose each person in the United States uses 12,000 kWh of electricity a year and the power plants using coal to generate electricity are 40% efficient. If 1.0 kg of burned coal releases 33.0 mJ a) how much coal will be burned during a year for a family of four b) how large a pile of coal would that be (using 2620 kg/ m^3) c) how much heat is given off to the environment




power= current x voltage, energy= power x time



I can find a) at 1800 w (watts), but I have no idea where to start on part b.
For 2, I'm unsure of where to star. I know the family of four would use 48,000 kWh a year, but after that, I'm lost
 
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CEF721 said:
1. An electric space heater draws 15.0 A from a 120 V source. It is operated, on average, for 5.0h (hours) each day. a) How much power does the heater use and b) At $.10 per kWh, what does it cost to operate the heater for 30 days?
2. Suppose each person in the United States uses 12,000 kWh of electricity a year and the power plants using coal to generate electricity are 40% efficient. If 1.0 kg of burned coal releases 33.0 mJ a) how much coal will be burned during a year for a family of four b) how large a pile of coal would that be (using 2620 kg/ m^3) c) how much heat is given off to the environment




power= current x voltage, energy= power x time



I can find a) at 1800 w (watts), but I have no idea where to start on part b.
For 2, I'm unsure of where to star. I know the family of four would use 48,000 kWh a year, but after that, I'm lost

A kWh is the energy equivalent to one kilowatt for one hour duration. As you may recall, a Watt is equivalent to a Joule per second (J/s). So a kWh is 1000 W x 1hr = 3.6 x 106 J.

For the first question you should be able to work out how many hours the heater runs in the 30 day period, and then find the kWh, etc.
 
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