Physics 10: Calculating Velocity of a Ball Launched from a Slingshot

AI Thread Summary
To calculate the velocity of a ball launched from a slingshot, the relevant parameters include the mass of the ball (0.675 kg), the force applied (3.50x10^2 N), and the distance pulled back (1.75 m). The potential energy stored in the slingshot can be calculated using the formula Ep(elas) = force x distance. This energy can then be converted into kinetic energy to find the velocity of the ball at release. The discussion emphasizes the need to determine which values—force or energy—are most useful for the calculation. Understanding these concepts is crucial for solving the problem effectively.
reesie
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Here's the question:
1. A ball with a mass of 0.675 kg was launched towards a wall. If it was pulled back a distance of 1.75 m in the slingshot using 3.50x10^2 N of force, what is the speed of the ball as it is released from the slingshot?
2. Ep(elas)=fxd?? that could possibly be divided by the mass to give you velocity
3...
I really have no idea and I really need help.
 
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They gave a spring constant and a distance. You can get both force and energy values from those given quantities. Which one do you want? In other words, what do you want, and which value will be more useful in obtaining what you want?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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