1. In the circuit shown below, describe what happens to the brightness of bulbs A and B when the switch is closed. Explain your reasoning. (no other information is given, just asking about the relative brightness of each bulb) ￼ In the circuit, with the switch open, you have a loop with a battery and bulbs A and B in series. When the switch closes, B becomes parallel with the electrical line that holds the switch. In this case, the electrical line that B is on is inside of the larger loop of the battery, A, and the switch. 2. Relevant equations V = IR 3. The attempt at a solution I thought at first that the bulbs would both slightly dim because the added switch and line would add a small amount of resistance to the line, but I see that A gets brighter and B goes out. Is this because the current takes the path of least resistance and skips over the B bulb?