Vlad137 said:
When you say that as the speed increases and the temperature drops, are you referring to the air which is being pulled into the system?
No, I'm talking about the exhaust gas temperature.
The temperature is basically a measure of the energy contained in matter (We call it
enthalpy). Every substance has a property called
heat capacity (
Cp) and the relation between its temperature (
T) and its
specific enthalpy (
h, which is the enthalpy compared to the mass of the substance) is
.
When you add motion to this substance, you add
kinetic energy that can be recovered if you decelerate it. That is what you do in a turbine. The amount of kinetic energy is
½mv², if you want to compare it with specific enthalpy, you have to divide it by the mass (
m), so the
specific kinetic energy is
½v². So the total enthalpy in a substance that is in motion is:
If you divide the previous equation by
Cp:
T0 is called the total temperature. It represents the temperature that would have the substance if it was decelerated to zero.
Now, when the exhaust gases enter the turbine it has a certain temperature and it goes a certain speed, which means we know its total enthalpy (
h0). The turbine will decelerate the flow of exhaust gas and use the removed energy to run the compressor. So its total enthalpy will drop, so will its total temperature. This means that if the exhaust gases were to decelerate by itself, it would have a certain increase in temperature (
½v²/Cp). With a turbine, the exit velocity will be smaller, so the temperature increase will also be smaller when at rest.
In summary:
- Temperature is a measure of energy;
- Speed can also be a measure of energy;
- A turbine convert energy into mechanical work;
- Therefore, once some energy is removed, the temperature and/or speed of the exhaust gas have to decrease.
Vlad137 said:
Also, how does the polytropic process demonstrate that both density and temperature will increase?
So we know that Pv = RT. Only R is known, so we need another equation to establish a relation between at least 2 of the 3 unknowns (P, v, T). The polytropic process stipulates that Pv
n = C or P = C / v
n, where C is a constant.
To eliminate C, we imagine a gas that is in 2 different states, 1 and 2, both states having their own properties P,v, and T. So, the polytropic process says that C = P
1v
1n. But the polytropic process says that C is also equal to P
2v
2n. So:
P
1v
1n = P
2v
2n
Or:
P2 / P1 = v1n / v2nAS long as n > 0, this proves that if v
1 > v
2 (or ρ
2 > ρ
1, according to the definition of
specific volume), then P
2 > P
1 (and vice-versa).
Furthermore, the ideal gas law says:
P
2 / P
1 = (RT
2 / v
2) / (RT
1 / v
1)
or:
P
2 / P
1 = T
2 / T
1 * v
1 / v
2
So the previous relationship can be rewritten as:
T
2 / T
1 * v
1 / v
2 = v
1n / v
2n
or:
T2 / T1 = v1n-1 / v2n-1
Combining the 2 relationships, we can find the following:
T2 / T1 = (P2 / P1)(n-1)/n
Again, as long as n > 1, this proves that if P
1 > P
2, then T
2 > T
1.
So both density and temperature are increased when the pressure is increased in a polytropic process when n > 1. In a compressor or turbine,
the process is adiabatic (or very close to it), so n is always greater than 1.