Physics coefficient of friction question

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A 17kg box is pushed with a 150N force and accelerates at 2.3m/s², leading to a calculation of the coefficient of friction. The normal force (Fn) is calculated as 166.6N, and the net force (Fnet) is determined to be 110.9N using the equation Fnet = 150 - (17)(2.3). The coefficient of friction (μ) is then found using the formula Fnet = μFn, resulting in μ = 0.66. The final answer is confirmed as correct, emphasizing the importance of showing work when asking for help.
Jasmin99
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Physics coefficient of friction question!

A 17kg box is being pushed by a 150N force. If the box is accelerating at 2.3m/s2. What is the coefficient of friction on the ground?FNet=μFn
Fn= 9.8x17= 166.6N
How can I find the fnet?
 
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Hi Jasmin99. Welcome to PF.

You should read the how to ask for help forum. Will you specify where you are having problem?.
 
Sorry! I'm not sure how to find the Fnet.
 
Okay. Can you draw the FBD of the object?
 
Here is my work:
Fnet= 150-(17)(2.3)
Fnet= 110.9N
Fnet=uFn
110.9=u166.6
U=0.66
Not sure if I did it right.
 
The answer looks correct
 
Thanks for the help everyone! I have figured it out now.
 
Jasmin99 said:
Here is my work:
Fnet= 150-(17)(2.3)
Fnet= 110.9N
Fnet=uFn
110.9=u166.6
U=0.66
Not sure if I did it right.

Yup, you've got it right. Make sure you post your attempt at the time of asking the question itself.
 
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